percentages Model Questions & Answers, Practice Test for ssc cgl tier 1 2023

ssc cgl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs

Number System

Ratio Proportion & Partnership

Averages

Percentages

Profit & Loss

Time & Work

Time & Distance

Simple Interest & Compound Interest

Mensuration: Area & Volumes

Algebraic Expressions

Linear Equations

Squareroots & Cuberoots

Click To More Exercise For Percentages
Question :11

Chunilal invests 65% in machinery, 20% in raw material and still has Rs. 1,305 cash with him. Find his total investment.

Answer: (d)

Let he had originally Rs. x.

Then 65% of x + 20 % of x + 1305 = x

0.65x + 0.2 x + 1305 = x

0.15 x = 1305 ⇒ x = Rs. 8700

∴ His total investment = 65% of 8700 + 20% of 8700

= 85% of 8700 = Rs. 7395

Question :12

The total population of a village is 5000. The number of males and females increases by 10% and 15% respectively and consequently the population of the village becomes 5600. What was the number of males in the village?

Answer: (b)

Let the number of males be x.

Then, number of females = (5000 – x).

∴ 10% of x + 15% of (5000 – x) = (5600 –5000)

$10/100x + 15/100(5000 - x) = 600$

⇒ 10x + 75000 - 15x = 60000.

⇒5x = 15000

x = 3000.

Question :13

If 50% of (x – y) = 40% of (x + y), then what per cent of x is y?

Answer: (a)

Given that, 50% of (x - y) = 40% of (x + y)

$50/100 × (x - y) = 40/100 × (x + y)$

5x - 5y = 4x + 4y

x = 9y ...(i)

Let r % of x = y

$r/100 × 9y = y$ [from Eq. (i)]

∴r = $100/9 = 11{1}/9 %$

Question :14

Mr. Nair's monthly salary is Rs.22,500. He took a loan of Rs.30,000 on simple interest for 3 years at the rate of 5 p.c.p.a The amount that he will be paying as simple interest in 3 years is what percent of his monthly salary?

Answer: (b)

SI = ${30,000 × 3 × 5}/100 = 4500$

x% of 22,500 = 4500

$x = {4500 × 100}/{22,500}$ = 20%

Question :15

The population of a town was 48600. It increased by 25% in the first year and decreased by 8% in the second year. What will be the population of the town at the end of 2 years?

Answer: (e)

Population after two years

= $48600 × 125/100 × 92/100$ = 55890

Click To More Exercise For Percentages
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